Base | Representation |
---|---|
bin | 1111111110111… |
… | …10011001110101 |
3 | 100100021222100021 |
4 | 13333132121311 |
5 | 233311030432 |
6 | 21145445141 |
7 | 3215443063 |
oct | 777363165 |
9 | 310258307 |
10 | 134080117 |
11 | 69759416 |
12 | 38aa07b1 |
13 | 21a16962 |
14 | 13b43033 |
15 | bb87697 |
hex | 7fde675 |
134080117 has 2 divisors, whose sum is σ = 134080118. Its totient is φ = 134080116.
The previous prime is 134080099. The next prime is 134080151. The reversal of 134080117 is 711080431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103510276 + 30569841 = 10174^2 + 5529^2 .
It is a cyclic number.
It is not a de Polignac number, because 134080117 - 27 = 134079989 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 134080091 and 134080100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134080157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67040058 + 67040059.
It is an arithmetic number, because the mean of its divisors is an integer number (67040059).
Almost surely, 2134080117 is an apocalyptic number.
It is an amenable number.
134080117 is a deficient number, since it is larger than the sum of its proper divisors (1).
134080117 is an equidigital number, since it uses as much as digits as its factorization.
134080117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 672, while the sum is 25.
The square root of 134080117 is about 11579.2969130254. The cubic root of 134080117 is about 511.8249587290.
The spelling of 134080117 in words is "one hundred thirty-four million, eighty thousand, one hundred seventeen".
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