Base | Representation |
---|---|
bin | 10011100000110000111… |
… | …001001111000001000111 |
3 | 11202011222011000212112022 |
4 | 103200300321033001013 |
5 | 133432030111401224 |
6 | 2503551131113355 |
7 | 165605341565534 |
oct | 23406071170107 |
9 | 4664864025468 |
10 | 1340850106439 |
11 | 477718a24838 |
12 | 197a47ba285b |
13 | 9959832455c |
14 | 48c7ca05d8b |
15 | 24d2a38065e |
hex | 13830e4f047 |
1340850106439 has 2 divisors, whose sum is σ = 1340850106440. Its totient is φ = 1340850106438.
The previous prime is 1340850106433. The next prime is 1340850106459. The reversal of 1340850106439 is 9346010580431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1340850106439 - 236 = 1272130629703 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1340850106439.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340850106433) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670425053219 + 670425053220.
It is an arithmetic number, because the mean of its divisors is an integer number (670425053220).
Almost surely, 21340850106439 is an apocalyptic number.
1340850106439 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340850106439 is an equidigital number, since it uses as much as digits as its factorization.
1340850106439 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 311040, while the sum is 44.
The spelling of 1340850106439 in words is "one trillion, three hundred forty billion, eight hundred fifty million, one hundred six thousand, four hundred thirty-nine".
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