Base | Representation |
---|---|
bin | 11000111110100110… |
… | …00001111001011001 |
3 | 1021121120020202220101 |
4 | 30133103001321121 |
5 | 204430423442324 |
6 | 10054354255401 |
7 | 653211661345 |
oct | 143723017131 |
9 | 37546222811 |
10 | 13409984089 |
11 | 576164a587 |
12 | 2722b87561 |
13 | 13592ca838 |
14 | 912dac625 |
15 | 537438944 |
hex | 31f4c1e59 |
13409984089 has 2 divisors, whose sum is σ = 13409984090. Its totient is φ = 13409984088.
The previous prime is 13409984087. The next prime is 13409984167. The reversal of 13409984089 is 98048990431.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11449000000 + 1960984089 = 107000^2 + 44283^2 .
It is a cyclic number.
It is not a de Polignac number, because 13409984089 - 21 = 13409984087 is a prime.
Together with 13409984087, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (13409984087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6704992044 + 6704992045.
It is an arithmetic number, because the mean of its divisors is an integer number (6704992045).
Almost surely, 213409984089 is an apocalyptic number.
It is an amenable number.
13409984089 is a deficient number, since it is larger than the sum of its proper divisors (1).
13409984089 is an equidigital number, since it uses as much as digits as its factorization.
13409984089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2239488, while the sum is 55.
The spelling of 13409984089 in words is "thirteen billion, four hundred nine million, nine hundred eighty-four thousand, eighty-nine".
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