13410010451143 has 4 divisors (see below), whose sum is σ = 13410018083448. Its totient is φ = 13410002818840.

The previous prime is 13410010451113. The next prime is 13410010451161. The reversal of 13410010451143 is 34115401001431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13410010451143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13410010451113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 297405 + ... + 5187337.

It is an arithmetic number, because the mean of its divisors is an integer number (3352504520862).

Almost surely, 2^{13410010451143} is an apocalyptic number.

13410010451143 is a deficient number, since it is larger than the sum of its proper divisors (7632305).

13410010451143 is an equidigital number, since it uses as much as digits as its factorization.

13410010451143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7632304.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 13410010451143 its reverse (34115401001431), we get a palindrome (47525411452574).

The spelling of 13410010451143 in words is "thirteen trillion, four hundred ten billion, ten million, four hundred fifty-one thousand, one hundred forty-three".