13410012520397 has 4 divisors (see below), whose sum is σ = 13411051505376. Its totient is φ = 13408973535420.

The previous prime is 13410012520379. The next prime is 13410012520417. The reversal of 13410012520397 is 79302521001431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13410012520397 - 2²² = 13410008326093 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13410012520397.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13410012520327) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 519473129 + ... + 519498942.

It is an arithmetic number, because the mean of its divisors is an integer number (3352762876344).

Almost surely, 2^{13410012520397} is an apocalyptic number.

It is an amenable number.

13410012520397 is a deficient number, since it is larger than the sum of its proper divisors (1038984979).

13410012520397 is a wasteful number, since it uses less digits than its factorization.

13410012520397 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1038984978.

The product of its (nonzero) digits is 45360, while the sum is 38.

The spelling of 13410012520397 in words is "thirteen trillion, four hundred ten billion, twelve million, five hundred twenty thousand, three hundred ninety-seven".