134100433231 has 4 divisors (see below), whose sum is σ = 134228027464. Its totient is φ = 133972839000.

The previous prime is 134100433217. The next prime is 134100433297. The reversal of 134100433231 is 132334001431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134100433231 - 2¹⁵ = 134100400463 is a prime.

It is a super-2 number, since 2×134100433231² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 134100433196 and 134100433205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134100433331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 63795540 + ... + 63797641.

It is an arithmetic number, because the mean of its divisors is an integer number (33557006866).

Almost surely, 2^134100433231 is an apocalyptic number.

134100433231 is a deficient number, since it is larger than the sum of its proper divisors (127594233).

134100433231 is a wasteful number, since it uses less digits than its factorization.

134100433231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127594232.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 134100433231 its reverse (132334001431), we get a palindrome (266434434662).

The spelling of 134100433231 in words is "one hundred thirty-four billion, one hundred million, four hundred thirty-three thousand, two hundred thirty-one".