Base | Representation |
---|---|
bin | 100111111101110… |
… | …0010111111011001 |
3 | 10110110100100201122 |
4 | 1033323202333121 |
5 | 10221244304011 |
6 | 341022255025 |
7 | 45142252541 |
oct | 11773427731 |
9 | 3413310648 |
10 | 1341009881 |
11 | 628a68632 |
12 | 315127475 |
13 | 184a96393 |
14 | ca158321 |
15 | 7cae13db |
hex | 4fee2fd9 |
1341009881 has 2 divisors, whose sum is σ = 1341009882. Its totient is φ = 1341009880.
The previous prime is 1341009877. The next prime is 1341009883. The reversal of 1341009881 is 1889001431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1307184025 + 33825856 = 36155^2 + 5816^2 .
It is a cyclic number.
It is not a de Polignac number, because 1341009881 - 22 = 1341009877 is a prime.
It is a super-2 number, since 2×13410098812 = 3596615001879268322, which contains 22 as substring.
Together with 1341009883, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1341009883) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670504940 + 670504941.
It is an arithmetic number, because the mean of its divisors is an integer number (670504941).
Almost surely, 21341009881 is an apocalyptic number.
It is an amenable number.
1341009881 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341009881 is an equidigital number, since it uses as much as digits as its factorization.
1341009881 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6912, while the sum is 35.
The square root of 1341009881 is about 36619.8017607960. The cubic root of 1341009881 is about 1102.7506589468.
The spelling of 1341009881 in words is "one billion, three hundred forty-one million, nine thousand, eight hundred eighty-one".
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