Base | Representation |
---|---|
bin | 1100001100100100101010… |
… | …1000110110101110111001 |
3 | 1202110222220201111110200220 |
4 | 3003021022220312232321 |
5 | 3224202431332401131 |
6 | 44304311110450253 |
7 | 2552564526203415 |
oct | 303111250665671 |
9 | 52428821443626 |
10 | 13410140122041 |
11 | 4300232551943 |
12 | 1606b84963989 |
13 | 763756034970 |
14 | 3450a8bc3d45 |
15 | 183c663bae96 |
hex | c324aa36bb9 |
13410140122041 has 16 divisors (see below), whose sum is σ = 19519360968576. Its totient is φ = 8139347427456.
The previous prime is 13410140122039. The next prime is 13410140122069. The reversal of 13410140122041 is 14022104101431.
It is a happy number.
13410140122041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 13410140122041 - 21 = 13410140122039 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13410140122091) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2355132405 + ... + 2355138098.
It is an arithmetic number, because the mean of its divisors is an integer number (1219960060536).
Almost surely, 213410140122041 is an apocalyptic number.
It is an amenable number.
13410140122041 is a deficient number, since it is larger than the sum of its proper divisors (6109220846535).
13410140122041 is a wasteful number, since it uses less digits than its factorization.
13410140122041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4710270592.
The product of its (nonzero) digits is 768, while the sum is 24.
Adding to 13410140122041 its reverse (14022104101431), we get a palindrome (27432244223472).
The spelling of 13410140122041 in words is "thirteen trillion, four hundred ten billion, one hundred forty million, one hundred twenty-two thousand, forty-one".
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