Base | Representation |
---|---|
bin | 111110011100100010… |
… | …0010111111010011011 |
3 | 110211010202111200101012 |
4 | 1330321010113322123 |
5 | 4144114431342021 |
6 | 141334431044135 |
7 | 12455105244626 |
oct | 1747104277233 |
9 | 424122450335 |
10 | 134101434011 |
11 | 51965844216 |
12 | 21ba637064b |
13 | c85181c66c |
14 | 66c20a4dbd |
15 | 374ce7335b |
hex | 1f39117e9b |
134101434011 has 4 divisors (see below), whose sum is σ = 134149007400. Its totient is φ = 134053860624.
The previous prime is 134101434007. The next prime is 134101434109. The reversal of 134101434011 is 110434101431.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 110434101431 = 43 ⋅2568234917.
It is a cyclic number.
It is not a de Polignac number, because 134101434011 - 22 = 134101434007 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (134101431011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23782466 + ... + 23788103.
It is an arithmetic number, because the mean of its divisors is an integer number (33537251850).
Almost surely, 2134101434011 is an apocalyptic number.
134101434011 is a deficient number, since it is larger than the sum of its proper divisors (47573389).
134101434011 is an equidigital number, since it uses as much as digits as its factorization.
134101434011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47573388.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 134101434011 its reverse (110434101431), we get a palindrome (244535535442).
The spelling of 134101434011 in words is "one hundred thirty-four billion, one hundred one million, four hundred thirty-four thousand, eleven".
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