1341020112433 has 4 divisors (see below), whose sum is σ = 1343186542960. Its totient is φ = 1338853681908.

The previous prime is 1341020112401. The next prime is 1341020112539. The reversal of 1341020112433 is 3342110201431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341020112433 - 2⁵ = 1341020112401 is a prime.

It is a super-2 number, since 2×1341020112433² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1341020112398 and 1341020112407.

It is not an unprimeable number, because it can be changed into a prime (1341020115433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1083214335 + ... + 1083215572.

It is an arithmetic number, because the mean of its divisors is an integer number (335796635740).

Almost surely, 2^{1341020112433} is an apocalyptic number.

It is an amenable number.

1341020112433 is a deficient number, since it is larger than the sum of its proper divisors (2166430527).

1341020112433 is an equidigital number, since it uses as much as digits as its factorization.

1341020112433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2166430526.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 1341020112433 its reverse (3342110201431), we get a palindrome (4683130313864).

The spelling of 1341020112433 in words is "one trillion, three hundred forty-one billion, twenty million, one hundred twelve thousand, four hundred thirty-three".