Base | Representation |
---|---|
bin | 1100001100100101101101… |
… | …1101101101001101101111 |
3 | 1202111000122101200021220212 |
4 | 3003021123131231031233 |
5 | 3224204021114142033 |
6 | 44304355113133035 |
7 | 2552604524502551 |
oct | 303113335551557 |
9 | 52430571607825 |
10 | 13410422412143 |
11 | 430036792a649 |
12 | 16070433ba17b |
13 | 76379c671823 |
14 | 3450d44a74d1 |
15 | 183c8107c748 |
hex | c325b76d36f |
13410422412143 has 4 divisors (see below), whose sum is σ = 13630265402568. Its totient is φ = 13190579421720.
The previous prime is 13410422412137. The next prime is 13410422412173. The reversal of 13410422412143 is 34121422401431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13410422412143 - 222 = 13410418217839 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13410422412133) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109921495121 + ... + 109921495242.
It is an arithmetic number, because the mean of its divisors is an integer number (3407566350642).
Almost surely, 213410422412143 is an apocalyptic number.
13410422412143 is a deficient number, since it is larger than the sum of its proper divisors (219842990425).
13410422412143 is an equidigital number, since it uses as much as digits as its factorization.
13410422412143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 219842990424.
The product of its (nonzero) digits is 18432, while the sum is 32.
Adding to 13410422412143 its reverse (34121422401431), we get a palindrome (47531844813574).
The spelling of 13410422412143 in words is "thirteen trillion, four hundred ten billion, four hundred twenty-two million, four hundred twelve thousand, one hundred forty-three".
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