13410433213141 has 4 divisors (see below), whose sum is σ = 13410441870912. Its totient is φ = 13410424555372.

The previous prime is 13410433213109. The next prime is 13410433213171. The reversal of 13410433213141 is 14131233401431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13410433213141 - 2⁵ = 13410433213109 is a prime.

It is a super-3 number, since 3×13410433213141³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13410433213171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1298191 + ... + 5339116.

It is an arithmetic number, because the mean of its divisors is an integer number (3352610467728).

Almost surely, 2^{13410433213141} is an apocalyptic number.

It is an amenable number.

13410433213141 is a deficient number, since it is larger than the sum of its proper divisors (8657771).

13410433213141 is an equidigital number, since it uses as much as digits as its factorization.

13410433213141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8657770.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 13410433213141 its reverse (14131233401431), we get a palindrome (27541666614572).

The spelling of 13410433213141 in words is "thirteen trillion, four hundred ten billion, four hundred thirty-three million, two hundred thirteen thousand, one hundred forty-one".