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1341043412143 = 5776547354997
BaseRepresentation
bin10011100000111100011…
…010101000110010101111
311202012110121202211002211
4103200330122220302233
5133432424103142033
62504022234231251
7165613206632161
oct23407432506257
94665417684084
101341043412143
11477808055216
12197aa0885527
13995c93a6826
1448c9a564931
1524d3c3162cd
hex1383c6a8caf

1341043412143 has 8 divisors (see below), whose sum is σ = 1343576550512. Its totient is φ = 1338510998016.

The previous prime is 1341043412131. The next prime is 1341043412201. The reversal of 1341043412143 is 3412143401431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1341043412143 - 237 = 1203604458671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341043412113) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3600121 + ... + 3955117.

It is an arithmetic number, because the mean of its divisors is an integer number (167947068814).

Almost surely, 21341043412143 is an apocalyptic number.

1341043412143 is a deficient number, since it is larger than the sum of its proper divisors (2533138369).

1341043412143 is an equidigital number, since it uses as much as digits as its factorization.

1341043412143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 362121.

The product of its (nonzero) digits is 13824, while the sum is 31.

Adding to 1341043412143 its reverse (3412143401431), we get a palindrome (4753186813574).

The spelling of 1341043412143 in words is "one trillion, three hundred forty-one billion, forty-three million, four hundred twelve thousand, one hundred forty-three".

Divisors: 1 577 6547 354997 3777619 204833269 2324165359 1341043412143