Base | Representation |
---|---|
bin | 1100001100100101110010… |
… | …0001100110111101110111 |
3 | 1202111000200122011122012112 |
4 | 3003021130201212331313 |
5 | 3224204040143243333 |
6 | 44304400550441235 |
7 | 2552605132010306 |
oct | 303113441467567 |
9 | 52430618148175 |
10 | 13410440212343 |
11 | 4300376988159 |
12 | 160704936321b |
13 | 7637a32648a5 |
14 | 3450d69bc43d |
15 | 183c828e6948 |
hex | c325c866f77 |
13410440212343 has 4 divisors (see below), whose sum is σ = 13410536208888. Its totient is φ = 13410344215800.
The previous prime is 13410440212333. The next prime is 13410440212357. The reversal of 13410440212343 is 34321204401431.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13410440212343 - 214 = 13410440195959 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13410440212333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 47788421 + ... + 48068222.
It is an arithmetic number, because the mean of its divisors is an integer number (3352634052222).
Almost surely, 213410440212343 is an apocalyptic number.
13410440212343 is a deficient number, since it is larger than the sum of its proper divisors (95996545).
13410440212343 is an equidigital number, since it uses as much as digits as its factorization.
13410440212343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 95996544.
The product of its (nonzero) digits is 27648, while the sum is 32.
Adding to 13410440212343 its reverse (34321204401431), we get a palindrome (47731644613774).
The spelling of 13410440212343 in words is "thirteen trillion, four hundred ten billion, four hundred forty million, two hundred twelve thousand, three hundred forty-three".
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