13410504400001 has 4 divisors (see below), whose sum is σ = 13474061293104. Its totient is φ = 13346947506900.

The previous prime is 13410504399979. The next prime is 13410504400021. The reversal of 13410504400001 is 10000440501431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13410504400001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 13410504400001.

It is not an unprimeable number, because it can be changed into a prime (13410504400021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31778446235 + ... + 31778446656.

It is an arithmetic number, because the mean of its divisors is an integer number (3368515323276).

Almost surely, 2^{13410504400001} is an apocalyptic number.

It is an amenable number.

13410504400001 is a deficient number, since it is larger than the sum of its proper divisors (63556893103).

13410504400001 is an equidigital number, since it uses as much as digits as its factorization.

13410504400001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 63556893102.

The product of its (nonzero) digits is 960, while the sum is 23.

Adding to 13410504400001 its reverse (10000440501431), we get a palindrome (23410944901432).

The spelling of 13410504400001 in words is "thirteen trillion, four hundred ten billion, five hundred four million, four hundred thousand, one".