Base | Representation |
---|---|
bin | 1100001100100110000001… |
… | …0110011101110100011001 |
3 | 1202111000212002221201022211 |
4 | 3003021200112131310121 |
5 | 3224204203111301103 |
6 | 44304411202315121 |
7 | 2552606541415630 |
oct | 303114026356431 |
9 | 52430762851284 |
10 | 13410504400153 |
11 | 43003aa139433 |
12 | 1607066958aa1 |
13 | 7637b3649a43 |
14 | 34510132a517 |
15 | 183c8837536d |
hex | c326059dd19 |
13410504400153 has 32 divisors (see below), whose sum is σ = 16670614917888. Its totient is φ = 10523520000000.
The previous prime is 13410504400127. The next prime is 13410504400171. The reversal of 13410504400153 is 35100440501431.
It is not a de Polignac number, because 13410504400153 - 213 = 13410504391961 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13410504400253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17235778 + ... + 17997028.
It is an arithmetic number, because the mean of its divisors is an integer number (520956716184).
Almost surely, 213410504400153 is an apocalyptic number.
It is an amenable number.
13410504400153 is a deficient number, since it is larger than the sum of its proper divisors (3260110517735).
13410504400153 is a wasteful number, since it uses less digits than its factorization.
13410504400153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 765313.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 13410504400153 its reverse (35100440501431), we get a palindrome (48510944901584).
The spelling of 13410504400153 in words is "thirteen trillion, four hundred ten billion, five hundred four million, four hundred thousand, one hundred fifty-three".
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