Base | Representation |
---|---|
bin | 1100001100100110001000… |
… | …0101010010001010110111 |
3 | 1202111000221010121121210202 |
4 | 3003021202011102022313 |
5 | 3224204233030403143 |
6 | 44304414121111115 |
7 | 2552610343350404 |
oct | 303114205221267 |
9 | 52430833547722 |
10 | 13410533450423 |
11 | 430041458031a |
12 | 160707462849b |
13 | 7637b967b655 |
14 | 34510512d2ab |
15 | 183c8abb2ab8 |
hex | c32621522b7 |
13410533450423 has 2 divisors, whose sum is σ = 13410533450424. Its totient is φ = 13410533450422.
The previous prime is 13410533450417. The next prime is 13410533450453. The reversal of 13410533450423 is 32405433501431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13410533450423 - 222 = 13410529256119 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13410533450453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705266725211 + 6705266725212.
It is an arithmetic number, because the mean of its divisors is an integer number (6705266725212).
Almost surely, 213410533450423 is an apocalyptic number.
13410533450423 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410533450423 is an equidigital number, since it uses as much as digits as its factorization.
13410533450423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 259200, while the sum is 38.
Adding to 13410533450423 its reverse (32405433501431), we get a palindrome (45815966951854).
The spelling of 13410533450423 in words is "thirteen trillion, four hundred ten billion, five hundred thirty-three million, four hundred fifty thousand, four hundred twenty-three".
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