Base | Representation |
---|---|
bin | 1100001100100110001001… |
… | …1111100100101100100101 |
3 | 1202111000221121120202100022 |
4 | 3003021202133210230211 |
5 | 3224204241311421203 |
6 | 44304414524524525 |
7 | 2552610456052541 |
oct | 303114237445445 |
9 | 52430847522308 |
10 | 13410540342053 |
11 | 4300418458088 |
12 | 16070769b0745 |
13 | 7637bac2243a |
14 | 345106004a21 |
15 | 183c8b5c4a38 |
hex | c32627e4b25 |
13410540342053 has 2 divisors, whose sum is σ = 13410540342054. Its totient is φ = 13410540342052.
The previous prime is 13410540341999. The next prime is 13410540342077. The reversal of 13410540342053 is 35024304501431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9482347152964 + 3928193189089 = 3079342^2 + 1981967^2 .
It is a cyclic number.
It is not a de Polignac number, because 13410540342053 - 28 = 13410540341797 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13410540342653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705270171026 + 6705270171027.
It is an arithmetic number, because the mean of its divisors is an integer number (6705270171027).
Almost surely, 213410540342053 is an apocalyptic number.
It is an amenable number.
13410540342053 is a deficient number, since it is larger than the sum of its proper divisors (1).
13410540342053 is an equidigital number, since it uses as much as digits as its factorization.
13410540342053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 86400, while the sum is 35.
Adding to 13410540342053 its reverse (35024304501431), we get a palindrome (48434844843484).
The spelling of 13410540342053 in words is "thirteen trillion, four hundred ten billion, five hundred forty million, three hundred forty-two thousand, fifty-three".
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