Base | Representation |
---|---|
bin | 1100001100100111111000… |
… | …1010010011110101110011 |
3 | 1202111002010222000221112210 |
4 | 3003021332022103311303 |
5 | 3224211214124430120 |
6 | 44304532550023203 |
7 | 2552625123433350 |
oct | 303117612236563 |
9 | 52432128027483 |
10 | 13411004530035 |
11 | 4300636484412 |
12 | 1607186347b03 |
13 | 763863148c98 |
14 | 34514b917627 |
15 | 183cb7216ce0 |
hex | c327e293d73 |
13411004530035 has 16 divisors (see below), whose sum is σ = 24522979712256. Its totient is φ = 6130744927968.
The previous prime is 13411004530009. The next prime is 13411004530051. The reversal of 13411004530035 is 53003540011431.
It is not a de Polignac number, because 13411004530035 - 225 = 13410970975603 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13411004529984 and 13411004530011.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63861926229 + ... + 63861926438.
It is an arithmetic number, because the mean of its divisors is an integer number (1532686232016).
Almost surely, 213411004530035 is an apocalyptic number.
13411004530035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13411004530035 is a deficient number, since it is larger than the sum of its proper divisors (11111975182221).
13411004530035 is a wasteful number, since it uses less digits than its factorization.
13411004530035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127723852682.
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 13411004530035 its reverse (53003540011431), we get a palindrome (66414544541466).
The spelling of 13411004530035 in words is "thirteen trillion, four hundred eleven billion, four million, five hundred thirty thousand, thirty-five".
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