1341102133 has 4 divisors (see below), whose sum is σ = 1532688160. Its totient is φ = 1149516108.

The previous prime is 1341102109. The next prime is 1341102143. The reversal of 1341102133 is 3312011431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341102133 - 2⁹ = 1341101621 is a prime.

It is a super-2 number, since 2×1341102133² = 3597109862274299378, which contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1341102133.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341102143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95793003 + ... + 95793016.

It is an arithmetic number, because the mean of its divisors is an integer number (383172040).

Almost surely, 2^1341102133 is an apocalyptic number.

It is an amenable number.

1341102133 is a deficient number, since it is larger than the sum of its proper divisors (191586027).

1341102133 is an equidigital number, since it uses as much as digits as its factorization.

1341102133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191586026.

The product of its (nonzero) digits is 216, while the sum is 19.

The square root of 1341102133 is about 36621.0613308790. The cubic root of 1341102133 is about 1102.7759455169.

Adding to 1341102133 its reverse (3312011431), we get a palindrome (4653113564).

The spelling of 1341102133 in words is "one billion, three hundred forty-one million, one hundred two thousand, one hundred thirty-three".