Base | Representation |
---|---|
bin | 1100001100100111111101… |
… | …0101110110100111011111 |
3 | 1202111002012100022001111021 |
4 | 3003021333111312213133 |
5 | 3224211234212131104 |
6 | 44304534534305011 |
7 | 2552625453652636 |
oct | 303117725664737 |
9 | 52432170261437 |
10 | 13411024333279 |
11 | 430064667a931 |
12 | 1607190ab8167 |
13 | 763867290991 |
14 | 3451503d051d |
15 | 183cb8d29754 |
hex | c327f5769df |
13411024333279 has 2 divisors, whose sum is σ = 13411024333280. Its totient is φ = 13411024333278.
The previous prime is 13411024333211. The next prime is 13411024333319. The reversal of 13411024333279 is 97233342011431.
It is a strong prime.
It is an emirp because it is prime and its reverse (97233342011431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13411024333279 - 211 = 13411024331231 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411024333379) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705512166639 + 6705512166640.
It is an arithmetic number, because the mean of its divisors is an integer number (6705512166640).
Almost surely, 213411024333279 is an apocalyptic number.
13411024333279 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411024333279 is an equidigital number, since it uses as much as digits as its factorization.
13411024333279 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 326592, while the sum is 43.
The spelling of 13411024333279 in words is "thirteen trillion, four hundred eleven billion, twenty-four million, three hundred thirty-three thousand, two hundred seventy-nine".
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