Base | Representation |
---|---|
bin | 1100001100101000000010… |
… | …0010110100111011000110 |
3 | 1202111002020202021012201012 |
4 | 3003022000202310323012 |
5 | 3224211304343331210 |
6 | 44304540535002222 |
7 | 2552626120323236 |
oct | 303120042647306 |
9 | 52432222235635 |
10 | 13411044511430 |
11 | 4300657001a95 |
12 | 1607197809372 |
13 | 76386b507207 |
14 | 345152d63cc6 |
15 | 183cba9b3305 |
hex | c32808b4ec6 |
13411044511430 has 32 divisors (see below), whose sum is σ = 25543438940160. Its totient is φ = 5055472262880.
The previous prime is 13411044511421. The next prime is 13411044511433. The reversal of 13411044511430 is 3411544011431.
It is a super-2 number, since 2×134110445114302 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13411044511433) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 184739744 + ... + 184812323.
It is an arithmetic number, because the mean of its divisors is an integer number (798232466880).
Almost surely, 213411044511430 is an apocalyptic number.
13411044511430 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13411044511430 is a deficient number, since it is larger than the sum of its proper divisors (12132394428730).
13411044511430 is a wasteful number, since it uses less digits than its factorization.
13411044511430 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 369552284.
The product of its (nonzero) digits is 11520, while the sum is 32.
Adding to 13411044511430 its reverse (3411544011431), we get a palindrome (16822588522861).
The spelling of 13411044511430 in words is "thirteen trillion, four hundred eleven billion, forty-four million, five hundred eleven thousand, four hundred thirty".
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