Base | Representation |
---|---|
bin | 1100001100101000000010… |
… | …0010110101010100010111 |
3 | 1202111002020202021021221002 |
4 | 3003022000202311110113 |
5 | 3224211304343404142 |
6 | 44304540535013515 |
7 | 2552626120331036 |
oct | 303120042652427 |
9 | 52432222237832 |
10 | 13411044513047 |
11 | 4300657003225 |
12 | 160719780a29b |
13 | 76386b507b7c |
14 | 345152d6471d |
15 | 183cba9b3a32 |
hex | c32808b5517 |
13411044513047 has 2 divisors, whose sum is σ = 13411044513048. Its totient is φ = 13411044513046.
The previous prime is 13411044513037. The next prime is 13411044513071. The reversal of 13411044513047 is 74031544011431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411044513047 - 28 = 13411044512791 is a prime.
It is a super-2 number, since 2×134110445130472 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13411044513047.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411044513037) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705522256523 + 6705522256524.
It is an arithmetic number, because the mean of its divisors is an integer number (6705522256524).
Almost surely, 213411044513047 is an apocalyptic number.
13411044513047 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411044513047 is an equidigital number, since it uses as much as digits as its factorization.
13411044513047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 80640, while the sum is 38.
Adding to 13411044513047 its reverse (74031544011431), we get a palindrome (87442588524478).
The spelling of 13411044513047 in words is "thirteen trillion, four hundred eleven billion, forty-four million, five hundred thirteen thousand, forty-seven".
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