Search a number
-
+
13411044513047 is a prime number
BaseRepresentation
bin1100001100101000000010…
…0010110101010100010111
31202111002020202021021221002
43003022000202311110113
53224211304343404142
644304540535013515
72552626120331036
oct303120042652427
952432222237832
1013411044513047
114300657003225
12160719780a29b
1376386b507b7c
14345152d6471d
15183cba9b3a32
hexc32808b5517

13411044513047 has 2 divisors, whose sum is σ = 13411044513048. Its totient is φ = 13411044513046.

The previous prime is 13411044513037. The next prime is 13411044513071. The reversal of 13411044513047 is 74031544011431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13411044513047 - 28 = 13411044512791 is a prime.

It is a super-2 number, since 2×134110445130472 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13411044513047.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13411044513037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705522256523 + 6705522256524.

It is an arithmetic number, because the mean of its divisors is an integer number (6705522256524).

Almost surely, 213411044513047 is an apocalyptic number.

13411044513047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411044513047 is an equidigital number, since it uses as much as digits as its factorization.

13411044513047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 80640, while the sum is 38.

Adding to 13411044513047 its reverse (74031544011431), we get a palindrome (87442588524478).

The spelling of 13411044513047 in words is "thirteen trillion, four hundred eleven billion, forty-four million, five hundred thirteen thousand, forty-seven".