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13411050000 = 24355293083
BaseRepresentation
bin11000111110101110…
…00110001000010000
31021121122020221001120
430133113012020100
5204431212100000
610054433202240
7653224021065
oct143727061020
937548227046
1013411050000
1157622083a7
122723400380
1313595b1a5a
149131a8c6c
155375996a0
hex31f5c6210

13411050000 has 240 divisors, whose sum is σ = 44811506880. Its totient is φ = 3451840000.

The previous prime is 13411049999. The next prime is 13411050031. The reversal of 13411050000 is 5011431.

It is a tau number, because it is divible by the number of its divisors (240).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 4348459 + ... + 4351541.

It is an arithmetic number, because the mean of its divisors is an integer number (186714612).

Almost surely, 213411050000 is an apocalyptic number.

13411050000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13411050000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22405753440).

13411050000 is an abundant number, since it is smaller than the sum of its proper divisors (31400456880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13411050000 is an equidigital number, since it uses as much as digits as its factorization.

13411050000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3148 (or 3122 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 13411050000 its reverse (5011431), we get a palindrome (13416061431).

The spelling of 13411050000 in words is "thirteen billion, four hundred eleven million, fifty thousand".