1341123134341 has 4 divisors (see below), whose sum is σ = 1346222462112. Its totient is φ = 1336023806572.

The previous prime is 1341123134297. The next prime is 1341123134359. The reversal of 1341123134341 is 1434313211431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1341123134341 - 2¹⁵ = 1341123101573 is a prime.

It is a super-2 number, since 2×1341123134341² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341123134371) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2549663491 + ... + 2549664016.

It is an arithmetic number, because the mean of its divisors is an integer number (336555615528).

Almost surely, 2^{1341123134341} is an apocalyptic number.

It is an amenable number.

1341123134341 is a deficient number, since it is larger than the sum of its proper divisors (5099327771).

1341123134341 is an equidigital number, since it uses as much as digits as its factorization.

1341123134341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5099327770.

The product of its digits is 10368, while the sum is 31.

Adding to 1341123134341 its reverse (1434313211431), we get a palindrome (2775436345772).

The spelling of 1341123134341 in words is "one trillion, three hundred forty-one billion, one hundred twenty-three million, one hundred thirty-four thousand, three hundred forty-one".