Base | Representation |
---|---|
bin | 10011100001000001010… |
… | …100000101001011100001 |
3 | 11202012200100101100111212 |
4 | 103201001110011023201 |
5 | 133433111122020424 |
6 | 2504034331315505 |
7 | 165615225223133 |
oct | 23410124051341 |
9 | 4665610340455 |
10 | 1341125579489 |
11 | 47784a476813 |
12 | 197b042abb95 |
13 | 99610415567 |
14 | 48ca7433053 |
15 | 24d4464710e |
hex | 138415052e1 |
1341125579489 has 2 divisors, whose sum is σ = 1341125579490. Its totient is φ = 1341125579488.
The previous prime is 1341125579429. The next prime is 1341125579537. The reversal of 1341125579489 is 9849755211431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1253089942225 + 88035637264 = 1119415^2 + 296708^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341125579489 is a prime.
It is a super-2 number, since 2×13411255794892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1341125579429) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670562789744 + 670562789745.
It is an arithmetic number, because the mean of its divisors is an integer number (670562789745).
Almost surely, 21341125579489 is an apocalyptic number.
It is an amenable number.
1341125579489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341125579489 is an equidigital number, since it uses as much as digits as its factorization.
1341125579489 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 10886400, while the sum is 59.
The spelling of 1341125579489 in words is "one trillion, three hundred forty-one billion, one hundred twenty-five million, five hundred seventy-nine thousand, four hundred eighty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •