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1341125579537 is a prime number
BaseRepresentation
bin10011100001000001010…
…100000101001100010001
311202012200100101100120122
4103201001110011030101
5133433111122021122
62504034331320025
7165615225223232
oct23410124051421
94665610340518
101341125579537
1147784a476857
12197b042b0015
13996104155a3
1448ca7433089
1524d44647142
hex13841505311

1341125579537 has 2 divisors, whose sum is σ = 1341125579538. Its totient is φ = 1341125579536.

The previous prime is 1341125579489. The next prime is 1341125579543. The reversal of 1341125579537 is 7359755211431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1341001056256 + 124523281 = 1158016^2 + 11159^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1341125579537 is a prime.

It is a super-2 number, since 2×13411255795372 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1341125579587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670562789768 + 670562789769.

It is an arithmetic number, because the mean of its divisors is an integer number (670562789769).

Almost surely, 21341125579537 is an apocalyptic number.

It is an amenable number.

1341125579537 is a deficient number, since it is larger than the sum of its proper divisors (1).

1341125579537 is an equidigital number, since it uses as much as digits as its factorization.

1341125579537 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3969000, while the sum is 53.

The spelling of 1341125579537 in words is "one trillion, three hundred forty-one billion, one hundred twenty-five million, five hundred seventy-nine thousand, five hundred thirty-seven".