Base | Representation |
---|---|
bin | 10011100001000001010… |
… | …100000101001100010001 |
3 | 11202012200100101100120122 |
4 | 103201001110011030101 |
5 | 133433111122021122 |
6 | 2504034331320025 |
7 | 165615225223232 |
oct | 23410124051421 |
9 | 4665610340518 |
10 | 1341125579537 |
11 | 47784a476857 |
12 | 197b042b0015 |
13 | 996104155a3 |
14 | 48ca7433089 |
15 | 24d44647142 |
hex | 13841505311 |
1341125579537 has 2 divisors, whose sum is σ = 1341125579538. Its totient is φ = 1341125579536.
The previous prime is 1341125579489. The next prime is 1341125579543. The reversal of 1341125579537 is 7359755211431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1341001056256 + 124523281 = 1158016^2 + 11159^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1341125579537 is a prime.
It is a super-2 number, since 2×13411255795372 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1341125579587) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670562789768 + 670562789769.
It is an arithmetic number, because the mean of its divisors is an integer number (670562789769).
Almost surely, 21341125579537 is an apocalyptic number.
It is an amenable number.
1341125579537 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341125579537 is an equidigital number, since it uses as much as digits as its factorization.
1341125579537 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3969000, while the sum is 53.
The spelling of 1341125579537 in words is "one trillion, three hundred forty-one billion, one hundred twenty-five million, five hundred seventy-nine thousand, five hundred thirty-seven".
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