13411404342433 has 4 divisors (see below), whose sum is σ = 13501413767700. Its totient is φ = 13321394917168.

The previous prime is 13411404342419. The next prime is 13411404342463. The reversal of 13411404342433 is 33424340411431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4042001683729 + 9369402658704 = 2010473^2 + 3060948^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411404342433 - 2³⁷ = 13273965388961 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13411404342392 and 13411404342401.

It is not an unprimeable number, because it can be changed into a prime (13411404342463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 45004712410 + ... + 45004712707.

It is an arithmetic number, because the mean of its divisors is an integer number (3375353441925).

Almost surely, 2^{13411404342433} is an apocalyptic number.

It is an amenable number.

13411404342433 is a deficient number, since it is larger than the sum of its proper divisors (90009425267).

13411404342433 is an equidigital number, since it uses as much as digits as its factorization.

13411404342433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 90009425266.

The product of its (nonzero) digits is 165888, while the sum is 37.

Adding to 13411404342433 its reverse (33424340411431), we get a palindrome (46835744753864).

The spelling of 13411404342433 in words is "thirteen trillion, four hundred eleven billion, four hundred four million, three hundred forty-two thousand, four hundred thirty-three".