Base | Representation |
---|---|
bin | 1100001100101001011010… |
… | …0101011101100101100011 |
3 | 1202111010012112002110200012 |
4 | 3003022112211131211203 |
5 | 3224213034030113102 |
6 | 44305041344515135 |
7 | 2552641230432101 |
oct | 303122645354543 |
9 | 52433175073605 |
10 | 13411414301027 |
11 | 4300826813426 |
12 | 160727b61baab |
13 | 7638c9ccbb22 |
14 | 34518a102c71 |
15 | 183cdd1aa752 |
hex | c329695d963 |
13411414301027 has 2 divisors, whose sum is σ = 13411414301028. Its totient is φ = 13411414301026.
The previous prime is 13411414300993. The next prime is 13411414301093. The reversal of 13411414301027 is 72010341411431.
13411414301027 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13411414301027 - 28 = 13411414300771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13411414300984 and 13411414301002.
It is not a weakly prime, because it can be changed into another prime (13411414301627) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705707150513 + 6705707150514.
It is an arithmetic number, because the mean of its divisors is an integer number (6705707150514).
Almost surely, 213411414301027 is an apocalyptic number.
13411414301027 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411414301027 is an equidigital number, since it uses as much as digits as its factorization.
13411414301027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 32.
Adding to 13411414301027 its reverse (72010341411431), we get a palindrome (85421755712458).
The spelling of 13411414301027 in words is "thirteen trillion, four hundred eleven billion, four hundred fourteen million, three hundred one thousand, twenty-seven".
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