Base | Representation |
---|---|
bin | 1100001100101001011010… |
… | …0101011101100110100101 |
3 | 1202111010012112002110202122 |
4 | 3003022112211131212211 |
5 | 3224213034030113333 |
6 | 44305041344515325 |
7 | 2552641230432224 |
oct | 303122645354645 |
9 | 52433175073678 |
10 | 13411414301093 |
11 | 4300826813486 |
12 | 160727b61bb45 |
13 | 7638c9ccbb73 |
14 | 34518a102cbb |
15 | 183cdd1aa798 |
hex | c329695d9a5 |
13411414301093 has 2 divisors, whose sum is σ = 13411414301094. Its totient is φ = 13411414301092.
The previous prime is 13411414301027. The next prime is 13411414301111. The reversal of 13411414301093 is 39010341411431.
13411414301093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10915213377124 + 2496200923969 = 3303818^2 + 1579937^2 .
It is a cyclic number.
It is not a de Polignac number, because 13411414301093 - 234 = 13394234431909 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411414300093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705707150546 + 6705707150547.
It is an arithmetic number, because the mean of its divisors is an integer number (6705707150547).
Almost surely, 213411414301093 is an apocalyptic number.
It is an amenable number.
13411414301093 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411414301093 is an equidigital number, since it uses as much as digits as its factorization.
13411414301093 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 35.
The spelling of 13411414301093 in words is "thirteen trillion, four hundred eleven billion, four hundred fourteen million, three hundred one thousand, ninety-three".
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