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1341142013113 = 7372751406417
BaseRepresentation
bin10011100001000010010…
…010110001010010111001
311202012201111022021012121
4103201002102301102321
5133433124323404423
62504040115441241
7165615515006440
oct23410222612271
94665644267177
101341142013113
11477858780621
12197b098b6221
139961394a5b6
1448ca96add57
1524d45ce145d
hex138424b14b9

1341142013113 has 8 divisors (see below), whose sum is σ = 1533145010432. Its totient is φ = 1149241836096.

The previous prime is 1341142013053. The next prime is 1341142013171. The reversal of 1341142013113 is 3113102411431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1341142013113 - 233 = 1332552078521 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1341142013173) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 25677120 + ... + 25729297.

It is an arithmetic number, because the mean of its divisors is an integer number (191643126304).

Almost surely, 21341142013113 is an apocalyptic number.

It is an amenable number.

1341142013113 is a deficient number, since it is larger than the sum of its proper divisors (192002997319).

1341142013113 is an equidigital number, since it uses as much as digits as its factorization.

1341142013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 51410151.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 1341142013113 its reverse (3113102411431), we get a palindrome (4454244424544).

The spelling of 1341142013113 in words is "one trillion, three hundred forty-one billion, one hundred forty-two million, thirteen thousand, one hundred thirteen".

Divisors: 1 7 3727 26089 51406417 359844919 191591716159 1341142013113