13411433131 has 2 divisors, whose sum is σ = 13411433132. Its totient is φ = 13411433130.

The previous prime is 13411433129. The next prime is 13411433143. The reversal of 13411433131 is 13133411431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13411433131 - 2¹ = 13411433129 is a prime.

It is a super-2 number, since 2×13411433131² (a number of 21 digits) contains 22 as substring.

Together with 13411433129, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13411433096 and 13411433105.

It is not a weakly prime, because it can be changed into another prime (13411433111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705716565 + 6705716566.

It is an arithmetic number, because the mean of its divisors is an integer number (6705716566).

Almost surely, 2^13411433131 is an apocalyptic number.

13411433131 is a deficient number, since it is larger than the sum of its proper divisors (1).

13411433131 is an equidigital number, since it uses as much as digits as its factorization.

13411433131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1296, while the sum is 25.

Adding to 13411433131 its reverse (13133411431), we get a palindrome (26544844562).

The spelling of 13411433131 in words is "thirteen billion, four hundred eleven million, four hundred thirty-three thousand, one hundred thirty-one".