13411441032433 has 4 divisors (see below), whose sum is σ = 13873904516340. Its totient is φ = 12948977548528.

The previous prime is 13411441032421. The next prime is 13411441032463. The reversal of 13411441032433 is 33423014411431.

13411441032433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 6223288601104 + 7188152431329 = 2494652^2 + 2681073^2 .

It is a cyclic number.

It is not a de Polignac number, because 13411441032433 - 2⁵ = 13411441032401 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13411441032403) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231231741910 + ... + 231231741967.

It is an arithmetic number, because the mean of its divisors is an integer number (3468476129085).

Almost surely, 2^{13411441032433} is an apocalyptic number.

It is an amenable number.

13411441032433 is a deficient number, since it is larger than the sum of its proper divisors (462463483907).

13411441032433 is an equidigital number, since it uses as much as digits as its factorization.

13411441032433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 462463483906.

The product of its (nonzero) digits is 41472, while the sum is 34.

Adding to 13411441032433 its reverse (33423014411431), we get a palindrome (46834455443864).

The spelling of 13411441032433 in words is "thirteen trillion, four hundred eleven billion, four hundred forty-one million, thirty-two thousand, four hundred thirty-three".