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13411441032434 = 228323695125499
BaseRepresentation
bin1100001100101001100000…
…1011011011110011110010
31202111010021101101120021022
43003022120023123303302
53224213112401014214
644305044141455442
72552642003565164
oct303123013336362
952433241346238
1013411441032434
11430083a9110a5
121607288571582
137639026cb123
1434518d8a0934
15183ce06dad8e
hexc32982dbcf2

13411441032434 has 8 divisors (see below), whose sum is σ = 20188246926000. Its totient is φ = 6682025390436.

The previous prime is 13411441032421. The next prime is 13411441032463. The reversal of 13411441032434 is 43423014411431.

13411441032434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a junction number, because it is equal to n+sod(n) for n = 13411441032394 and 13411441032403.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11847562184 + ... + 11847563315.

It is an arithmetic number, because the mean of its divisors is an integer number (2523530865750).

Almost surely, 213411441032434 is an apocalyptic number.

13411441032434 is a deficient number, since it is larger than the sum of its proper divisors (6776805893566).

13411441032434 is a wasteful number, since it uses less digits than its factorization.

13411441032434 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 23695125784.

The product of its (nonzero) digits is 55296, while the sum is 35.

Adding to 13411441032434 its reverse (43423014411431), we get a palindrome (56834455443865).

The spelling of 13411441032434 in words is "thirteen trillion, four hundred eleven billion, four hundred forty-one million, thirty-two thousand, four hundred thirty-four".

Divisors: 1 2 283 566 23695125499 47390250998 6705720516217 13411441032434