Base | Representation |
---|---|
bin | 1100001100101001100000… |
… | …1011011011110011110010 |
3 | 1202111010021101101120021022 |
4 | 3003022120023123303302 |
5 | 3224213112401014214 |
6 | 44305044141455442 |
7 | 2552642003565164 |
oct | 303123013336362 |
9 | 52433241346238 |
10 | 13411441032434 |
11 | 430083a9110a5 |
12 | 1607288571582 |
13 | 7639026cb123 |
14 | 34518d8a0934 |
15 | 183ce06dad8e |
hex | c32982dbcf2 |
13411441032434 has 8 divisors (see below), whose sum is σ = 20188246926000. Its totient is φ = 6682025390436.
The previous prime is 13411441032421. The next prime is 13411441032463. The reversal of 13411441032434 is 43423014411431.
13411441032434 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a junction number, because it is equal to n+sod(n) for n = 13411441032394 and 13411441032403.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11847562184 + ... + 11847563315.
It is an arithmetic number, because the mean of its divisors is an integer number (2523530865750).
Almost surely, 213411441032434 is an apocalyptic number.
13411441032434 is a deficient number, since it is larger than the sum of its proper divisors (6776805893566).
13411441032434 is a wasteful number, since it uses less digits than its factorization.
13411441032434 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 23695125784.
The product of its (nonzero) digits is 55296, while the sum is 35.
Adding to 13411441032434 its reverse (43423014411431), we get a palindrome (56834455443865).
The spelling of 13411441032434 in words is "thirteen trillion, four hundred eleven billion, four hundred forty-one million, thirty-two thousand, four hundred thirty-four".
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