Base | Representation |
---|---|
bin | 1100001100101001100011… |
… | …0110000101010011100101 |
3 | 1202111010022011102120101002 |
4 | 3003022120312011103211 |
5 | 3224213123231244303 |
6 | 44305045221243045 |
7 | 2552642200611041 |
oct | 303123066052345 |
9 | 52433264376332 |
10 | 13411452212453 |
11 | 4300846157889 |
12 | 1607290263485 |
13 | 763904b13b19 |
14 | 345191171021 |
15 | 183ce1698788 |
hex | c3298d854e5 |
13411452212453 has 2 divisors, whose sum is σ = 13411452212454. Its totient is φ = 13411452212452.
The previous prime is 13411452212401. The next prime is 13411452212479. The reversal of 13411452212453 is 35421225411431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12592966503649 + 818485708804 = 3548657^2 + 904702^2 .
It is a cyclic number.
It is not a de Polignac number, because 13411452212453 - 210 = 13411452211429 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411452212153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705726106226 + 6705726106227.
It is an arithmetic number, because the mean of its divisors is an integer number (6705726106227).
Almost surely, 213411452212453 is an apocalyptic number.
It is an amenable number.
13411452212453 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411452212453 is an equidigital number, since it uses as much as digits as its factorization.
13411452212453 is an evil number, because the sum of its binary digits is even.
The product of its digits is 115200, while the sum is 38.
Adding to 13411452212453 its reverse (35421225411431), we get a palindrome (48832677623884).
The spelling of 13411452212453 in words is "thirteen trillion, four hundred eleven billion, four hundred fifty-two million, two hundred twelve thousand, four hundred fifty-three".
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