13411453004023 has 4 divisors (see below), whose sum is σ = 13463637646320. Its totient is φ = 13359268361728.

The previous prime is 13411453003969. The next prime is 13411453004051. The reversal of 13411453004023 is 32040035411431.

13411453004023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13411453004023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13411453004423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 26092320763 + ... + 26092321276.

It is an arithmetic number, because the mean of its divisors is an integer number (3365909411580).

Almost surely, 2^{13411453004023} is an apocalyptic number.

13411453004023 is a deficient number, since it is larger than the sum of its proper divisors (52184642297).

13411453004023 is an equidigital number, since it uses as much as digits as its factorization.

13411453004023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 52184642296.

The product of its (nonzero) digits is 17280, while the sum is 31.

Adding to 13411453004023 its reverse (32040035411431), we get a palindrome (45451488415454).

The spelling of 13411453004023 in words is "thirteen trillion, four hundred eleven billion, four hundred fifty-three million, four thousand, twenty-three".