Base | Representation |
---|---|
bin | 1100001100101001101111… |
… | …1101110000010101010111 |
3 | 1202111010102210220212022221 |
4 | 3003022123331300111113 |
5 | 3224213230131232401 |
6 | 44305054331203211 |
7 | 2552643404534200 |
oct | 303123375602527 |
9 | 52433383825287 |
10 | 13411504555351 |
11 | 4300872758881 |
12 | 16072a58a6507 |
13 | 76391290c756 |
14 | 3451980b85a7 |
15 | 183ce60877a1 |
hex | c329bf70557 |
13411504555351 has 24 divisors (see below), whose sum is σ = 15646778226576. Its totient is φ = 11461993482240.
The previous prime is 13411504555343. The next prime is 13411504555381. The reversal of 13411504555351 is 15355540511431.
It is not a de Polignac number, because 13411504555351 - 23 = 13411504555343 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13411504555298 and 13411504555307.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13411504555321) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23330455 + ... + 23898391.
It is an arithmetic number, because the mean of its divisors is an integer number (651949092774).
Almost surely, 213411504555351 is an apocalyptic number.
13411504555351 is a deficient number, since it is larger than the sum of its proper divisors (2235273671225).
13411504555351 is an equidigital number, since it uses as much as digits as its factorization.
13411504555351 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 569359 (or 569352 counting only the distinct ones).
The product of its (nonzero) digits is 450000, while the sum is 43.
The spelling of 13411504555351 in words is "thirteen trillion, four hundred eleven billion, five hundred four million, five hundred fifty-five thousand, three hundred fifty-one".
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