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1341151327152 = 243572132971263
BaseRepresentation
bin10011100001000010110…
…110010011001110110000
311202012202010211110200000
4103201002312103032300
5133433134214432102
62504041051230000
7165615660121200
oct23410266231660
94665663743600
101341151327152
11477862a6237a
12197b10a48300
139961585bb70
1448caaa16400
1524d46a3101c
hex13842d933b0

1341151327152 has 1440 divisors, whose sum is σ = 5134801351680. Its totient is φ = 335423047680.

The previous prime is 1341151327091. The next prime is 1341151327169. The reversal of 1341151327152 is 2517231511431.

1341151327152 is a `hidden beast` number, since 1 + 34 + 1 + 151 + 327 + 152 = 666.

It is a super-2 number, since 2×13411513271522 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is an unprimeable number.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 5099434573 + ... + 5099434835.

It is an arithmetic number, because the mean of its divisors is an integer number (3565834272).

Almost surely, 21341151327152 is an apocalyptic number.

1341151327152 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1341151327152, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2567400675840).

1341151327152 is an abundant number, since it is smaller than the sum of its proper divisors (3793650024528).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1341151327152 is a wasteful number, since it uses less digits than its factorization.

1341151327152 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 413 (or 388 counting only the distinct ones).

The product of its digits is 25200, while the sum is 36.

Adding to 1341151327152 its reverse (2517231511431), we get a palindrome (3858382838583).

The spelling of 1341151327152 in words is "one trillion, three hundred forty-one billion, one hundred fifty-one million, three hundred twenty-seven thousand, one hundred fifty-two".