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1341151327151 = 1936948970607
BaseRepresentation
bin10011100001000010110…
…110010011001110101111
311202012202010211110122222
4103201002312103032233
5133433134214432101
62504041051225555
7165615660121166
oct23410266231657
94665663743588
101341151327151
11477862a62379
12197b10a482bb
139961585bb6c
1448caaa163dd
1524d46a3101b
hex13842d933af

1341151327151 has 4 divisors (see below), whose sum is σ = 1348100297952. Its totient is φ = 1334202356352.

The previous prime is 1341151327091. The next prime is 1341151327169. The reversal of 1341151327151 is 1517231511431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1341151327151 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1341151320151) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3474485111 + ... + 3474485496.

It is an arithmetic number, because the mean of its divisors is an integer number (337025074488).

Almost surely, 21341151327151 is an apocalyptic number.

1341151327151 is a deficient number, since it is larger than the sum of its proper divisors (6948970801).

1341151327151 is an equidigital number, since it uses as much as digits as its factorization.

1341151327151 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6948970800.

The product of its digits is 12600, while the sum is 35.

Adding to 1341151327151 its reverse (1517231511431), we get a palindrome (2858382838582).

The spelling of 1341151327151 in words is "one trillion, three hundred forty-one billion, one hundred fifty-one million, three hundred twenty-seven thousand, one hundred fifty-one".

Divisors: 1 193 6948970607 1341151327151