Base | Representation |
---|---|
bin | 1100001100101001110110… |
… | …0111101111111111101111 |
3 | 1202111010111202012112101121 |
4 | 3003022131213233333233 |
5 | 3224213304234404411 |
6 | 44305101202521411 |
7 | 2552644162651453 |
oct | 303123547577757 |
9 | 52433452175347 |
10 | 13411532341231 |
11 | 4300887406812 |
12 | 16072b3066267 |
13 | 7639185ba9bb |
14 | 34519ba6c663 |
15 | 183ce8725571 |
hex | c329d9effef |
13411532341231 has 2 divisors, whose sum is σ = 13411532341232. Its totient is φ = 13411532341230.
The previous prime is 13411532341211. The next prime is 13411532341243. The reversal of 13411532341231 is 13214323511431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13411532341231 - 227 = 13411398123503 is a prime.
It is a super-2 number, since 2×134115323412312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411532341211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705766170615 + 6705766170616.
It is an arithmetic number, because the mean of its divisors is an integer number (6705766170616).
Almost surely, 213411532341231 is an apocalyptic number.
13411532341231 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411532341231 is an equidigital number, since it uses as much as digits as its factorization.
13411532341231 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25920, while the sum is 34.
Adding to 13411532341231 its reverse (13214323511431), we get a palindrome (26625855852662).
The spelling of 13411532341231 in words is "thirteen trillion, four hundred eleven billion, five hundred thirty-two million, three hundred forty-one thousand, two hundred thirty-one".
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