Base | Representation |
---|---|
bin | 11000111110110011… |
… | …10011011101001111 |
3 | 1021121200120222221001 |
4 | 30133121303131033 |
5 | 204431402304301 |
6 | 10054500321131 |
7 | 653233035652 |
oct | 143731633517 |
9 | 37550528831 |
10 | 13411759951 |
11 | 5762652837 |
12 | 27236a31a7 |
13 | 135979cc45 |
14 | 913311899 |
15 | 537689c01 |
hex | 31f67374f |
13411759951 has 2 divisors, whose sum is σ = 13411759952. Its totient is φ = 13411759950.
The previous prime is 13411759913. The next prime is 13411759973. The reversal of 13411759951 is 15995711431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13411759951 is a prime.
It is a super-3 number, since 3×134117599513 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13411759981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6705879975 + 6705879976.
It is an arithmetic number, because the mean of its divisors is an integer number (6705879976).
Almost surely, 213411759951 is an apocalyptic number.
13411759951 is a deficient number, since it is larger than the sum of its proper divisors (1).
13411759951 is an equidigital number, since it uses as much as digits as its factorization.
13411759951 is an evil number, because the sum of its binary digits is even.
The product of its digits is 170100, while the sum is 46.
The spelling of 13411759951 in words is "thirteen billion, four hundred eleven million, seven hundred fifty-nine thousand, nine hundred fifty-one".
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