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134120314310302 = 2277242094430163
BaseRepresentation
bin11110011111101101010001…
…101100010000111010011110
3122120212202222022022012212201
4132133231101230100322132
5120034411400430412202
61153130004413122114
740151605263400555
oct3637552154207236
9576782868265781
10134120314310302
113980a118a119a1
12130614b9a8933a
1359ab6507064b8
14251965a4a0d9c
151078b9cde3387
hex79fb51b10e9e

134120314310302 has 8 divisors (see below), whose sum is σ = 201906754756776. Its totient is φ = 66818062724712.

The previous prime is 134120314310291. The next prime is 134120314310303. The reversal of 134120314310302 is 203013413021431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134120314310303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 121047214528 + ... + 121047215635.

It is an arithmetic number, because the mean of its divisors is an integer number (25238344344597).

Almost surely, 2134120314310302 is an apocalyptic number.

134120314310302 is a deficient number, since it is larger than the sum of its proper divisors (67786440446474).

134120314310302 is a wasteful number, since it uses less digits than its factorization.

134120314310302 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 242094430442.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 134120314310302 its reverse (203013413021431), we get a palindrome (337133727331733).

The spelling of 134120314310302 in words is "one hundred thirty-four trillion, one hundred twenty billion, three hundred fourteen million, three hundred ten thousand, three hundred two".

Divisors: 1 2 277 554 242094430163 484188860326 67060157155151 134120314310302