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13412045335551 = 311575138623267
BaseRepresentation
bin1100001100101011110000…
…1100101010101111111111
31202111011211111111100022020
43003022330030222233333
53224220332101214201
644305224130051223
72552662662225642
oct303127414525777
952434744440266
1013412045335551
11430101aa38a65
121607416a19b13
1376399a972535
14345209c47a59
15183d287a8a36
hexc32bc32abff

13412045335551 has 8 divisors (see below), whose sum is σ = 17882882070144. Its totient is φ = 8941286079000.

The previous prime is 13412045335547. The next prime is 13412045335621. The reversal of 13412045335551 is 15553354021431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13412045335551 - 22 = 13412045335547 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13412045333551) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18964381 + ... + 19658886.

It is an arithmetic number, because the mean of its divisors is an integer number (2235360258768).

Almost surely, 213412045335551 is an apocalyptic number.

13412045335551 is a deficient number, since it is larger than the sum of its proper divisors (4470836734593).

13412045335551 is a wasteful number, since it uses less digits than its factorization.

13412045335551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 38739021.

The product of its (nonzero) digits is 540000, while the sum is 42.

Adding to 13412045335551 its reverse (15553354021431), we get a palindrome (28965399356982).

The spelling of 13412045335551 in words is "thirteen trillion, four hundred twelve billion, forty-five million, three hundred thirty-five thousand, five hundred fifty-one".

Divisors: 1 3 115751 347253 38623267 115869801 4470681778517 13412045335551