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134121122114 = 279580080151
BaseRepresentation
bin111110011101000111…
…1011110100101000010
3110211012010112221101012
41330322033132211002
54144140001401424
6141340413040522
712455434504430
oct1747217364502
9424163487335
10134121122114
1151975971181
1221bb0a86142
13c855923b25
1466c494bd50
15374ea61b0e
hex1f3a3de942

134121122114 has 8 divisors (see below), whose sum is σ = 229921923648. Its totient is φ = 57480480900.

The previous prime is 134121122111. The next prime is 134121122123. The reversal of 134121122114 is 411221121431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 134121122114.

It is not an unprimeable number, because it can be changed into a prime (134121122111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4790040062 + ... + 4790040089.

It is an arithmetic number, because the mean of its divisors is an integer number (28740240456).

Almost surely, 2134121122114 is an apocalyptic number.

134121122114 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

134121122114 is a deficient number, since it is larger than the sum of its proper divisors (95800801534).

134121122114 is an equidigital number, since it uses as much as digits as its factorization.

134121122114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9580080160.

The product of its digits is 384, while the sum is 23.

Adding to 134121122114 its reverse (411221121431), we get a palindrome (545342243545).

The spelling of 134121122114 in words is "one hundred thirty-four billion, one hundred twenty-one million, one hundred twenty-two thousand, one hundred fourteen".

Divisors: 1 2 7 14 9580080151 19160160302 67060561057 134121122114