13412113333 has 4 divisors (see below), whose sum is σ = 13420751148. Its totient is φ = 13403475520.

The previous prime is 13412113291. The next prime is 13412113339. The reversal of 13412113333 is 33331121431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 33331121431 = 19 ⋅1754269549.

It can be written as a sum of positive squares in 2 ways, for example, as 2014842769 + 11397270564 = 44887^2 + 106758^2 .

It is a cyclic number.

It is not a de Polignac number, because 13412113333 - 2²⁹ = 12875242421 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13412113298 and 13412113307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13412113339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4316578 + ... + 4319683.

It is an arithmetic number, because the mean of its divisors is an integer number (3355187787).

Almost surely, 2^13412113333 is an apocalyptic number.

It is an amenable number.

13412113333 is a deficient number, since it is larger than the sum of its proper divisors (8637815).

13412113333 is an equidigital number, since it uses as much as digits as its factorization.

13412113333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8637814.

The product of its digits is 1944, while the sum is 25.

Adding to 13412113333 its reverse (33331121431), we get a palindrome (46743234764).

The spelling of 13412113333 in words is "thirteen billion, four hundred twelve million, one hundred thirteen thousand, three hundred thirty-three".