Base | Representation |
---|---|
bin | 10011100001000110100… |
… | …111000001011100101111 |
3 | 11202012220112120110220102 |
4 | 103201012213001130233 |
5 | 133433301343243043 |
6 | 2504051223541315 |
7 | 165620354363405 |
oct | 23410647013457 |
9 | 4665815513812 |
10 | 1341214431023 |
11 | 477895643235 |
12 | 197b29bba83b |
13 | 9962595482c |
14 | 48cb5161475 |
15 | 24d4c3486b8 |
hex | 138469c172f |
1341214431023 has 2 divisors, whose sum is σ = 1341214431024. Its totient is φ = 1341214431022.
The previous prime is 1341214431017. The next prime is 1341214431101. The reversal of 1341214431023 is 3201344121431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1341214431023 - 28 = 1341214430767 is a prime.
It is a super-2 number, since 2×13412144310232 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1341214431013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670607215511 + 670607215512.
It is an arithmetic number, because the mean of its divisors is an integer number (670607215512).
Almost surely, 21341214431023 is an apocalyptic number.
1341214431023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1341214431023 is an equidigital number, since it uses as much as digits as its factorization.
1341214431023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1341214431023 its reverse (3201344121431), we get a palindrome (4542558552454).
The spelling of 1341214431023 in words is "one trillion, three hundred forty-one billion, two hundred fourteen million, four hundred thirty-one thousand, twenty-three".
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