Base | Representation |
---|---|
bin | 11110011111101111001001… |
… | …010011010011101111010101 |
3 | 122120212222011011022100112221 |
4 | 132133233021103103233111 |
5 | 120034430003141043242 |
6 | 1153130535500142341 |
7 | 40152006101305546 |
oct | 3637571123235725 |
9 | 576788134270487 |
10 | 134122321034197 |
11 | 3980aa587312a1 |
12 | 13061979b379b1 |
13 | 59ab8b03961a2 |
14 | 25197aabca4cd |
15 | 1078c69183167 |
hex | 79fbc94d3bd5 |
134122321034197 has 2 divisors, whose sum is σ = 134122321034198. Its totient is φ = 134122321034196.
The previous prime is 134122321034099. The next prime is 134122321034237. The reversal of 134122321034197 is 791430123221431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 105249420064996 + 28872900969201 = 10259114^2 + 5373351^2 .
It is a cyclic number.
It is not a de Polignac number, because 134122321034197 - 239 = 133572565220309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134122321034297) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061160517098 + 67061160517099.
It is an arithmetic number, because the mean of its divisors is an integer number (67061160517099).
Almost surely, 2134122321034197 is an apocalyptic number.
It is an amenable number.
134122321034197 is a deficient number, since it is larger than the sum of its proper divisors (1).
134122321034197 is an equidigital number, since it uses as much as digits as its factorization.
134122321034197 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 217728, while the sum is 43.
The spelling of 134122321034197 in words is "one hundred thirty-four trillion, one hundred twenty-two billion, three hundred twenty-one million, thirty-four thousand, one hundred ninety-seven".
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