Base | Representation |
---|---|
bin | 11110011111101111010000… |
… | …100010000100110001000111 |
3 | 122120212222110121120121102202 |
4 | 132133233100202010301013 |
5 | 120034430230220024133 |
6 | 1153130555512225115 |
7 | 40152012103401131 |
oct | 3637572042046107 |
9 | 576788417517382 |
10 | 134122442345543 |
11 | 39810010159303 |
12 | 130619b269b19b |
13 | 59ab8cc55bc52 |
14 | 25197bcd68051 |
15 | 1078c74b472e8 |
hex | 79fbd0884c47 |
134122442345543 has 2 divisors, whose sum is σ = 134122442345544. Its totient is φ = 134122442345542.
The previous prime is 134122442345483. The next prime is 134122442345579. The reversal of 134122442345543 is 345543244221431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 134122442345543 - 210 = 134122442344519 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134322442345543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061221172771 + 67061221172772.
It is an arithmetic number, because the mean of its divisors is an integer number (67061221172772).
Almost surely, 2134122442345543 is an apocalyptic number.
134122442345543 is a deficient number, since it is larger than the sum of its proper divisors (1).
134122442345543 is an equidigital number, since it uses as much as digits as its factorization.
134122442345543 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5529600, while the sum is 47.
Adding to 134122442345543 its reverse (345543244221431), we get a palindrome (479665686566974).
The spelling of 134122442345543 in words is "one hundred thirty-four trillion, one hundred twenty-two billion, four hundred forty-two million, three hundred forty-five thousand, five hundred forty-three".
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