Base | Representation |
---|---|
bin | 111110011101001011… |
… | …1000110011001111011 |
3 | 110211012021022110022021 |
4 | 1330322113012121323 |
5 | 4144141004322001 |
6 | 141340523535311 |
7 | 12455460466051 |
oct | 1747227063173 |
9 | 424167273267 |
10 | 134123120251 |
11 | 5197700642a |
12 | 21bb168a537 |
13 | c856173463 |
14 | 66c4d0c1d1 |
15 | 374ed08ba1 |
hex | 1f3a5c667b |
134123120251 has 2 divisors, whose sum is σ = 134123120252. Its totient is φ = 134123120250.
The previous prime is 134123120227. The next prime is 134123120279. The reversal of 134123120251 is 152021321431.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 134123120251 - 211 = 134123118203 is a prime.
It is a super-2 number, since 2×1341231202512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (134123126251) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67061560125 + 67061560126.
It is an arithmetic number, because the mean of its divisors is an integer number (67061560126).
Almost surely, 2134123120251 is an apocalyptic number.
134123120251 is a deficient number, since it is larger than the sum of its proper divisors (1).
134123120251 is an equidigital number, since it uses as much as digits as its factorization.
134123120251 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 134123120251 its reverse (152021321431), we get a palindrome (286144441682).
The spelling of 134123120251 in words is "one hundred thirty-four billion, one hundred twenty-three million, one hundred twenty thousand, two hundred fifty-one".
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