Base | Representation |
---|---|
bin | 1100001100101101001010… |
… | …0110001100000100100111 |
3 | 1202111012210200121101200102 |
4 | 3003023102212030010213 |
5 | 3224222114301440031 |
6 | 44305325312334315 |
7 | 2553005204332142 |
oct | 303132246140447 |
9 | 52435720541612 |
10 | 13412421124391 |
11 | 43011a3077753 |
12 | 160750084439b |
13 | 763a2a7879b3 |
14 | 345243b09059 |
15 | 183d4b7887cb |
hex | c32d298c127 |
13412421124391 has 2 divisors, whose sum is σ = 13412421124392. Its totient is φ = 13412421124390.
The previous prime is 13412421124367. The next prime is 13412421124409. The reversal of 13412421124391 is 19342112421431.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13412421124391 - 214 = 13412421108007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13412421024391) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6706210562195 + 6706210562196.
It is an arithmetic number, because the mean of its divisors is an integer number (6706210562196).
Almost surely, 213412421124391 is an apocalyptic number.
13412421124391 is a deficient number, since it is larger than the sum of its proper divisors (1).
13412421124391 is an equidigital number, since it uses as much as digits as its factorization.
13412421124391 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 41472, while the sum is 38.
The spelling of 13412421124391 in words is "thirteen trillion, four hundred twelve billion, four hundred twenty-one million, one hundred twenty-four thousand, three hundred ninety-one".
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